Extension to the latter question: 2) Calculate the molar of each of these forms

Question

Extension to the latter question:
2) Calculate the molar of each of these forms of glutamic acid -taking into account any counter ions that are present.
a) 148.1 g + 35.4527= 183.55961 g
b) 147.09891 g
c) 146.09091+ 22.989770 = 169.08068 g
d) 145.08291 + 2(22.989770) = 191.06245 g

Extension to the latter question:
3) Calculate the molar mass of the fully protonated form ofglutamic acid + its counter ion and calculate the number ofmillimoles present in a 525 mg.
183.55961 g / 1000 g = 0.18355961 mg = 1 mol
525 mg / 0.18355961 mg = 2860 mmol

Is my answer correct?

Explanation / Answer

a) 148.1 g + 35.4527= 183.55961 g if 183.55961 g-molar mass of glutamic acid is correct, thenYOUR ANSWER IS CORRECT.

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