1.How are H° and qsys related? Question options: H° = qsys H° = -qsys -H° = qsys

Question

1.How are H° and qsys related? Question options: H° = qsys H° = -qsys -H° = qsys H° = qsys + qsurr

2.In the equilibrium expression for the dissolution of urea, why don't the water and solid urea appear in the expression.

Question options:

We just forgot them, whoops.

They are not part of the reaction.

We are only interested in the dissolved urea.

Pure solids and pure liquids do not appear in an equilibrium expression.

3.

Which of the following is the best to use to determine the spontaneity of the dissolution of urea.

Question options:

H°

G°

S°

K

We just forgot them, whoops.

They are not part of the reaction.

We are only interested in the dissolved urea.

Pure solids and pure liquids do not appear in an equilibrium expression.

3.

Which of the following is the best to use to determine the spontaneity of the dissolution of urea.

Question options:

H°

G°

S°

K

Explanation / Answer

1)
Ho is heat change in the system
Answer:
H° = qsys

2)
pure solid and pure liquid are never considered while writing Kc expression
Answer:    
Pure solids and pure liquids do not appear in an equilibrium expression.

3)
Spontaneity is decided by G°
if G° is negative, reaction is considered spontaneous
if G° is positive, reaction is non spontaneous

Answer: G°

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