± pH of a Strong Acid and a Strong Base Can you please help with part C??? The t

Question

± pH of a Strong Acid and a Strong Base

Can you please help with part C???

The temperature for each solution is carried out at approximately 297 K where Kw=1.00×1014 .

Part A

0.85 g of hydrogen chloride (HCl ) is dissolved in water to make 8.0 L of solution. What is the pH of the resulting hydrochloric acid solution?

Express the pH numerically to two decimal places.

2.54

Part B

0.55 g of sodium hydroxide (NaOH ) pellets are dissolved in water to make 2.0 L of solution. What is the pH of this solution?

Express the pH numerically to two decimal places.

11.84

Part C

What is the pOH of the solution in Part B?

Express the pOH numerically to two decimal places.

pOH=???

2.54

Explanation / Answer

Ans part C

To find the pOH of solution in part B we can use formula

pH + pOH = 14

pH is 11.84 ( from part B)

So 11.84 + pOH = 14

pOH = 14 - 11.84

=2.16

so the pOH of solution is 2.16

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