GENERAL CHEMISTRY 003 SPRING 2017 TUESDAY SECTION Quiz 8 MULTIPLE CHOICE. Choose
ID: 502584 • Letter: G
Question
GENERAL CHEMISTRY 003 SPRING 2017 TUESDAY SECTION Quiz 8 MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) Using the following equation for the combustion of octane, calculate the amount of moles of oxygen that with 100.0gof octane. The molar mass of octane g/mole. The molar ts mass of carbon dioxide is 44.0095 g/mole. 208H18 2502 16 CO2 18 H20 L1H 11018 kl A) 10.93 moles B) 6.997 moles 14.00 moles D) 18.18 moles 2 A 35.6gsample of ethanol (C2H5OH) isburned in a bomb imeter, according to the following reaction. If the temperature rose from 35.0 to 76.0 Cand the heat capacity of the calorimeter kJWoc, what is the value of DH ran? The molar mass of ethanol is 46.07 g/mol. C2H50H(1 3020g) 2CO%) 3H20(g) A)-8.09 x 103 kU/mol B) +1.24 x 103 kJ/mol C) +9.55 x 103 kJ/mol D)-9.55 x 103 kWmol E) 1.24 x 103 kWmol for the following reaction AH 3) Use the standard reaction enthalpiesgiven below todetermine 2 NO(g) O2(g) 2 NO2 g) Given: +183 kJ AH 150. kJ D) +238 kJ A) +115 kJ 4) Define specific heat capacity. A) the quantity of heat required to lower the temperature of 1 gram of a substance by 1°F the quantity of heat required to raise the temperature of 1 gram of a substance by 1 C the quantity of heat required to lower the temperature of 1 liter of a substance by 1 c D) the quantity of heat required to lower the temperature of 1 mole of a substance by 1 c the quantity ofheat required to change a system'stemperature by 1 C uring the reaction of 51.2 gof Al, according to the reaction below? 5) How much energy is evolved d Assume that there is excess Fe2O3. Fe203(s) 2 Al(s) Al203(s) 2 Fe(s) -852 kJ C) 224 kJ E) 1617 A) 808 kJ B) 448 kJExplanation / Answer
1) 2 moles of octane reacts with 25 moles of oxygen
or, 2 x 114.33 gm of octane reacts with 25 x 32 gm of oxygen
or, 100 gm of octane reacts with = [(25 x 32) / (2 x 114.33) ] x 100 = 349.86 gm
moles of oxygen = 349.86 gm / 32 gm mol-1 = 10.93 moles
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