When gaseous carbon monoxide and hydrogen are combined in a scaled vessel and he

Question

When gaseous carbon monoxide and hydrogen are combined in a scaled vessel and heated they will eventually form an equilibrium mixture of reactants and products according to the balanced chemical equilibrium below. CO(g) + 3H_2(g) CH_4(g) + H_2O(g) In one such reaction 3 moles of one reactant were combined with 1 mole of the other reactant in a fixed volume vessel and heated to 1200 K. Analysis of the reaction mixture at various times gave the results below. Which component of the reaction mixture is represented by curve B? carbon monoxide either methane or water hydrogen either hydrogen or carbon monoxide not enough information to decide Which of the following is/are true concerning a chemical reaction at equilibrium? The system will be a mixture of reactant and products. The rate of the forward and reverse reactions are equal. The amount of each reactant and product is constant. 1 only 2 only 3 only 1 and 2 1, 2, and 3 The following reaction is investigated (assume an ideal gas mixture): 2N_2O(g) + N_2H_4(g) 3N_2(g) + 2H_2O(g) Initially there are 0.100 mol of N_2O and 0.25 mol of N_2H_4. in a 10.0-L container. If there are 0.062 mol of N_2O at equilibrium, how many moles of N_2are present at equilibrium?

Explanation / Answer

Here CO represents the curve B. Because you can observe that curve A is very slant means it's H2 which is decreasing at 3 times the rate of decreasing CO and curve C represents products .

So answer is CO

2)

All the three are correct

3)

Moles of N2O recated = initial - final = 0.100- 0.062 = 0.038 moles

From reaction, 2 moles N2O reacts to give 3 moles of N2

So final moles of N2 = 3/2 * 0.038 = 0.057 moles

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.