An organism has a diploid number of 8 (2n=8). In a cell undergoing meiosis, one

Question

An organism has a diploid number of 8 (2n=8). In a cell undergoing meiosis, one of the homologues fails to disjoin at the first meiotic division. This causes both homologues of the pair to proceed to the same pole.  

a. How many chromatids would be present in each daughter cell that results from meiosis I?  

b. If the second meiotic division separates all sister chromatids, how many chromosomes would be present in the resulting gametes?

c. Using n to designate one complete haploid set of chromosomes, indicate the chromosome complement of the gametes of part b.   

Explanation / Answer

a) If 2n=8 so 4 chromosomes should go to each cell but as one pair didnt disjoin so the daughter cells will have 5 and 3 chromatids

b) second meiotic division is similar to mitosis , number of chromosomes doesn't change so the daughter cells will have 5 and 3 chromosomes

so in the end there will be 4 daughter cells two with 5 chromosomes and two with 3 chromosomes

2n=8 , so it will become n=4 but as one chromatid doesnt separate so 5 in one cell and 3 in other cell

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