1. Consider the following two molecules, which would you expect to have the high
ID: 503254 • Letter: 1
Question
1. Consider the following two molecules, which would you expect to have the higher wave number for c Cand why? Are either of these molecules conjugated? 2. Identify the structure of the molecule (C6H7N) with the following IR spectrum. 100 60- 40 20- CoHTN 4500 4000 3500 3000 2500 2000 1500 1000 500 Wavenumbers (cm 1) 3. The IR spectra for cyclohexanone and cyclobutanone are shown, in which compound is the C o bond stronger? How do you know? 100 80 8 60 40 20 4500 4000 3500 3000 2500 2000 1500 1000 500 4500 4000 3500 3000 2500 2000 1500 1000 500 wave numbers (cm 1) Wave numbers (cm 1)Explanation / Answer
Answer for Q1: In these two compounds first compound has higher wavenumber comoare to second compound, because it contains carbonyl group. And both compounds are not conjugated. Conjugted compound means it should contain minimum two double bonds.
Answer for Q2: The compund is Aniline (C6H5NH2). In genreal NH2 will come at 3000-3500 cm-1 and in this spectra there is a strong peak at ~3300 cm-1. It shows that presence of NH2 grooup. Based on this and molecular formula it is Aniline.
Answer for Q3:The IR value for cyclo butanone (~1780 cm-1) is more than cyclo hexanone (1710 cm-1). When the size of the ring reduces there will be more starian, this lead to higher IR value.
Answer for Q6: Yes,there will be lot of difference incase of methyl group. In compound A methyl group will come around 4-4.2, because it connected to elocronegative atom 'O' followed by electron with drawing group (carbonyl), so more deshileded and it will expose to more magnetic field. In second compound methyl will come around 2.1-2.3. Here it connect to electron with drawing group(carbonyl) followed by Oxygen,here methyl less shilded compare to previous case.
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