organic Chemistry ll (CHM 344) Test on Infrared and NMR (Ch 13 and LA) 03/30/17
ID: 503928 • Letter: O
Question
organic Chemistry ll (CHM 344) Test on Infrared and NMR (Ch 13 and LA) 03/30/17 1. (a) Convert a wavenumber of 4000 cm 1 to wavelength in um. (b) Convert a wavelength of 5.5 um to wavenumber in cm 2. Fill in each blank with wavenumber or wavelength: is directly proportional to frequency. is directly proportional to energy. 3 What property of a chemical bond permits it to absorb infrared radiation (R-active)? 4 specifically describe the differences in infrared absorption frequencies which would allow you to distinguish between the following three molecules. Give the absorption frequencies above 1600 cm for each bond and make a statement about the distinguishing features. H-CEC-H H3C-CEC-CH3 H3C-CEC-HExplanation / Answer
Ans 1 - µm = 10,000/cm-1
a) 4000cm-1 = 2500nm =2.5µm
b) 5.5µm = 1818.18 cm-1
Ans 2 - Fill in the blanks -
a) wave number
b) wave number
as wave number is inversly proportional to wave length and direct praportional to frequency.
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