Do the right thing. [Appropriate units, sig figs, legibility, coherence, ethics,
ID: 504112 • Letter: D
Question
Do the right thing. [Appropriate units, sig figs, legibility, coherence, ethics, ...] Use textbook or instructor's web pages for needed conversions, constants, values, etc. Use values from random web pages may not be correct and will result in no credit. Give 2 sig figs for all results. Calculate the pH of a 1.50 M solution of HF, a weak acid (K_a = 6.8 times 10^-4) HF + H O H_3O^+ F^- Calculate the pH of a 1.50 M solution of the weak add, hypochlorous acid. (K_a = 2.9 times 10^-8) HClO + H_2O H_2O^+ + Calculate the pH of a 2.50 M solution of hypochlorous acid. A 1.00 M solution of butanoic acid, a weak acid, has a pH of 2.41. Calculate the K_a for butanoic acid. HBu + H_2O H_2O^+ + Bu^- [HBu = C_3H_2COOH] Calculate the pH of a 1.00 M solution of methylamine, a weak base, (K_b = 4.4 times 10) CH_ NH_2 + H_2O CH_ NH^_3 + OH^-Explanation / Answer
1)
for simplicity lets write weak acid as HF
HF -----> H+ + F-
1.50 0 0
1.50-x x x
Ka = [H+][F-]/[HF]
Ka = x*x/(c-x)
since ka is small, x will be small and it can be ignored as compared to c
So, above expression becomes
Ka = x*x/(c)
so, x = sqrt (Ka*c)
x = sqrt ((6.80E-04)*1.50) = 3.19E-02
pH = -log [H+] = -log (3.19E-02) = 1.50
Answer: 1.50
I am allowed to answer only 1 question at a time
Related Questions
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.