In our lab experiment, we filtered CaCl and CaOH2 solutions that we prepared the

Question

In our lab experiment, we filtered CaCl and CaOH2 solutions that we prepared the previous week and transferred both of the filtrates using a 25 ml pipette into two erlenmeyer flasks. We then prepared the standard HCl by pipeting 100 ml of HCl to prepare 250 ml of 0.04M HCl from the 0.1 M HCl solution that we initially had. We pipeted 100 ml of HCl into a 250 ml volumetric flask and diluted to the mark. The buret was filled with the prepared HCl and both the CaCl and CaOH2 were titrated until a yellow endpoint was reached, this titration was repeated three times for each solution.

The result for solubility of Ca(OH)2= 0.1571

solubility for CaCl2=0.1299

Q. Do you expect the two solutions to have similar solubility? Explain why or why not.

Explanation / Answer

Ca(OH)2 is sparingly soluble and its solubility product,Ksp is 5.5 × 10^-6

CaCl2 is completely soluble

So, we could not expect both will be similar solubility and even we cannot compare solubilities of these two compounds

Solubility of CaCl2 is 74.5g/100ml of water at 20°C

Solubility of Ca(OH)2 is 0.173g/100ml of water at 20°C

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