_______CuSO_4(aq) + _ NaOH_(aq) rightarrow _ Cu(OH)_2(aq) + _ NaSO_4(aq) Observa

Question

_______CuSO_4(aq) + _ NaOH_(aq) rightarrow _ Cu(OH)_2(aq) + _ NaSO_4(aq) Observations before heating: Cu(OH)_2(s) rightarrow Observations after heating: Full Equation: _HCl_(aq) + _ Na_2CO_3(aq) rightarrow _ H_2O_(l) + _ CO_2(l) + _ NaCl_(aq) TIE NIE _NH_4Cl_(aq) + _ NaOH_(aq) rightarrow _ NH_4OH_(aq) + _ NaCl_(aq) _ NH_4OH_(aq) rightarrow Observations: Full Equation: TIE NIE What does the net ionic equation tell you about the reaction? Net Reactions of Oxidation Reduction Reactions: _CuSO_4(aq) + _ Zn_(s) rightarrow Observations: Oxidation Half Reaction: Reduction Half Reaction: Net Reaction

Explanation / Answer

SOLUTION:

Q9. CuSO4 (aq) + 2NaOH (aq) --------------> Cu(OH)2(s) + Na2SO4 (aq)

Observation before heating - No precipitate.

Cu(OH)2(s) ---> Cu2+ + 2OH-

Observation after heating - precipitation.

Full Equation ; 2HCl(aq) + Na2CO3 (aq) ------> H2O(l) + CO2(g) + 2NaCl(aq)

TIE = 2H+(aq) + 2Cl-(aq) + 2Na+(aq) + CO32-(aq) ---------> H2O(l) + CO2(g) + 2Na+(aq) + 2Cl-(aq)

NIE = 2H+(aq) + CO32-(aq) ---------> H2O(l) + CO2(g)

Q10.

NH4Cl(aq)+ NaOH(aq) -----> NH4OH(aq) + NaCl(aq)

NH4OH(aq) ------>NH3(g) + H2O(l)

TIE = NH4+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) ---------> NH3 (g) + H2O(l) + Na+(aq) + Cl-(aq)

NIE = NH4+(aq) + OH-(aq) ---------> NH3 (g) + H2O(l)

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