I am doing an organic chemistry lab and need to find out how to do this problem

Question

I am doing an organic chemistry lab and need to find out how to do this problem

add 3 moles of diethylamine for every one mole of alpha-chloro-2,6-dimethylacetanilide

the moles for alpha-chloro-2,6-dimethylacetanilide is 0.0203 mol

I need to find how much diethylamine to add per alpha-chloro-2,6-dimethylacetanilide

Place the product from last week in a dry 50 mL round-bottom flask and dissolve it in 25 mLof toluene. Then add 3 moles of diethylamine for every one mole of a chloro-2, 6-dimethylacetanilide. Fit the flask with a condensor, add a boiling chip, and reflux vigorously for 90 minutes. After the reflux period is cover, cool the reaction flask, stopper with a cork, an let stand until the next laboratory period. After standing for a week, crystals will have separated from the reaction mixture. Add an additional 10 mL of toluene and cool the mixture in an ice bath to 10oC. Remove the crysta

Explanation / Answer

3 moles of diethylamine for every one mole of alpha-chloro-2,6-dimethylacetanilide

i.e stoichiometric ratio of diethylamine to alpha-chloro-2,6-dimethylacetanilide is 3 : 1

Hence for 1 mole alpha-chloro-2,6-dimethylacetanilide we need to add 3 moles of diethylamine

For 0.0203 mole alpha-chloro-2,6-dimethylacetanilide we need to add = 3 x 0.0203 = 0.0609 moles of diethylamine

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