Does the pressure of air initially in the flask introduce an error? Explain your

Question

Does the pressure of air initially in the flask introduce an error? Explain your answer Is it necessary to consider the pressure of water vapor initially in the flask? Explain your answer. Briefly discuss whether each of the following "mistakes" would produce a high result, a low result, or make no difference in the value obtained for the gas constant, R. i. The water level in the flask dropped below the tip of tube C. ii. Loss of some potassium chlorate from the test tube. iii. Incomplete decomposition of the potassium chlorate. iv. The correction for the vapor pressure of water was omitted in the calculation. v. Failure to use the Mno catalyst. Why is it necessary to equalize the pressure of the receiving beaker and the flask before measuring the delivered volume of water?

Explanation / Answer

Q1.

P of air initially in flask produces error --> True

since the Pressure of air is actually occupying a certain space, meaning it also attributes for moles of substance/gas

Q2.

Yes, we must include the vapor pressure of the vapor, since it is included in the gas mixture

It also will change our final vlaue of "Pressure of Gas" being studied since

Ptotal = Pvapor + Pgas

sometimes, Pvapor can be ignored, but it is the best of practices to include it in the formula

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