A student performed the lodate Analysis and found that it took 7.80 mL of 0.02 M

Question

A student performed the lodate Analysis and found that it took 7.80 mL of 0.02 M Na_2S_2O_3 to rate 4.00 mL of saturated copper iodate. Answer the following questions: Using the balanced equations on page 79, what is the mole ratio of triiodide, I_3^-, to thiosulfate, S_2O_3^2? What is the mole ratio of iodate, IO_3^+, to triiodide, I_3? Calculate the number of moles of iodate in 7.80 mL of 0.02 M Na_2S_2O_3. What is the iodate concentration in the 4.00 mL of saturated copper iodate solution? Use this value to find the K_sp value for copper iodate?

Explanation / Answer

But you aremost likely talking about the redox reaction of:

IO3 + 8 I + 6 H+ ---> 3 I3 + 3 H2O

In which we use redox of IO3 and 8I (with 6h+ help, in acidic media) to form the aquoeus I3- ion

therefore,

1 mol of IO3- reacts with 8 mol of I- to form 3 mol of I3-

then

1 mol of IO3 per 3 mol of I3-

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