Write down the quotients Q for the following reactions: N_2 3H_2 rightarrow 2NH_

Question

Write down the quotients Q for the following reactions: N_2 3H_2 rightarrow 2NH_3, CO + 2H_2 rightarrow CH_3OH, 2 NO + O_2 2NO_2 Consider the reactions CO + H_2O rightarrow CO_2 H_2 and CH_4 H_2O CO 3H_2 The equilibrium constant for the first reaction is K_1 = 1.4 and for the second K_2 5.3 times 10^-3 M^2. Here M is the common unit of concentration in chemistry M mol/l kmol/m^3. What is the equilibrium constant for the reaction CH_4 2 H_2O rightarrow CO_2 4 H_2 Assume that the following reaction, 2H_2S + CH_4 rightarrow 4H_2 CS_2 has an equilibrium constant K = 4.56, where the unit is an appropriate power of M Given the following equilibrium concentrations nH_2s = 0.15 M nCH_4 = 0.56 M, and ncs_2 = 0.37 M, what is the equilibrium concentration of H_2?

Explanation / Answer

(a) Q = [NH3]^2/[N2][H2]^3

Q =[CH3OH]/[CO][H2]^2

Q = [NO2]^2/[NO]^2[O2]

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(b)

Keq = k1 * K2 = 1.4 * 5.3*10^-3 =0.00742

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Keq = [H2]^4[CS2]/[Ch4][H2S]^2

or, 4.56 = [H2]^4 * 0.37/0.56 *(0.15)^2

or, [H2]^4 = 0.155

or, [H2] = 0.628 M

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