2950280620819b4a placeholder 12850 edu. Printing is for personal, private use on

Question

2950280620819b4a placeholder 12850 edu. Printing is for personal, private use only. No part of this bgok may be reproduced ar thout publisher's prior permission. Violators will be prosecuted. Name Section Experiment 9 Data and Calculations: Molar Mass of a Volatile Liquid Trial I Trial 2 Mass of flask and stopper Mass of flask, and 25 66 425. Mass of flask, stopper and water direction only iftold to do sot) Temperature of boiling water bath Atmospheric Gambient) presure Calculations and Results Presure of vapor, P Volume of flask (volume of vapor. V Temperature of vapor, T

Explanation / Answer

Calculation of molar mass of volatile liquid

Trial 2

mass of vapor = 124.42 - 124.18

                        = 0.24 g

Volume of flask (V) = (425.85 - 124.18)g/1 g/ml x 1000 [density of water = 1 g/ml]

                               = 0.30167 L

Temperature (T) = 99.5 + 273

                           = 372.5 K

Atmospheric pressure = 760 mmHg

                                    = 1 atm

R = gas constant

moles of vapor = PV/RT

                         = 1 x 0.30167/0.08205 x 372.5

                         = 0.0099 mol

molar mass of unknown = mass of vapor/moles of vapor

                                       = 0.24 g/0.0099 mol

                                       = 24.24 g/mol

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