roscopic Explorer (FUSE) satellite has been analyzing the spectra of emission so

Question

roscopic Explorer (FUSE) satellite has been analyzing the spectra of emission sources within the Milky Way. Among the satellite's findings a containing oxygen atoms that have lost five electrons write an electron configuration for these highly ionized oxygen atoms. Use the orbital diagram tool to add the orbitals, on the orbitals to add the electrons. Make sure you add electrons according to Hund's rule. Which electrons have been removed from the neutral atoms? O 1 2s electron and 4 2p electrons O 2 2s electrons and 3 2p electrons

Explanation / Answer

1. electronic configuration of highly ionized oxygen atoms

1s2 2s1

2. The answer is

1 2s electron and 4 2p electrons

3. E = hv = hc/

= hc/E = 6.626 * 10-34 * 3 * 108 / 18.2 * 10-18 = 1.09 * 10-8 m = 10.9 nm

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