Attempts score 04/7/2017 11:00 PM (A 68.5/100 G3/29/20170853 PM Gradebook s Prin

Question

Attempts score 04/7/2017 11:00 PM (A 68.5/100 G3/29/20170853 PM Gradebook s Print calaulamor Periodic Table Question 20 of 27 14 Sapling Learning For a particular reaction at 153.7 c, AG 177.74 kJ, and AS 330.17 JMK. Calculate AG for this reaction at -11.1 °C. 17 95 Number 18 kJ 26 Previous Gve un s View sa ation Check Answer Next Ext 27 2011 2017 Sapling Learning Inc. about US careers partners priva Poho terms se contact Resources CAssignme Available Fr Due Date: Points Possil Grade Categ Description: Policies. You can check up on any que You can keep t you getit right You lose 5% of in your questio O eTextbook O Help with Thi o Web Help & v O Technical Sup

Explanation / Answer

At 153.7 oC,

T = 153.7 oC = (153.7 + 273.1) K = 426.8 K

G = 177.75 KJ

S = 330.17 J/K = 0.33017 KJ/K

use:

G = H - TS

177.75 = H - 426.8*0.33017

H = 318.40 KJ

now H and S doesn’t change with temperature much.

so,

at -11.1 oC

T = (-11.1 + 273.1) K = 262 K

use:

G = H - TS

= 318.40 - 262 * 0.33017

= 231.9 KJ

Answer: 231.8 KJ

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