In an experiment, 0.327 g of zinc metal reacts to produce 0.407 g of zinc oxide.

Question

In an experiment, 0.327 g of zinc metal reacts to produce 0.407 g of zinc oxide. Using the conservation of mass law, predict the mass of reacting oxygen gas. 2 Zn(s) + O_2(g) rightarrow^delta 2 ZnO(s) A) 0.160 g B) 1.468 g C) 0.080 g D) 0.734 g E) 0.040 g What is the mass of aluminum metal that reacts to give 11.1 g of manganese metal? _MnO_2(l) + _Al(l) rightarrow^delta _Mn(l) + _Al_2O_3(s) A) 7.27 g B) 8.18 g C) 4.09 g D) 5.45 g E) 3.64 g What volume of oxygen gas reacts with 30.0 L of sulfur dioxide gas? (Assume temperature and pressure remain constant.) _SO_2(g) + _O_2(g) rightarrow^V_2O_5/650 degree C _SO_3(g) A) 30.0 L B) 10.0 L C) 60.0 L D) 15.0 L E) none of the above Starting with 1.56 g of salicylic acid, a student prepares 1.75 g of aspirin. If the calculated mass of aspirin is 1.88 g, what is the percent yield? A) 121% B) 93.1% C) 107%. D) 83.0% E) 89.1%

Explanation / Answer

Q22.

m = 0.327 g of Zn

m = 0.407 g of ZnO

apply balance to find

mass of Oxygen gas

mol of ZnO = mass/MW = 0.407/81.408 = 0.004999 mol of ZnO

so

ratio is 1 mol of O2 is requied per 2 mol of ZnO

so

0.004999 mol o fZnO2 --> 0.004999/2 = 0.0024995 mol of O2

mass = mol*MW = 0.0024995*32 = 0.079984 g

nearest answer is C, 0.080 g

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.