For a parallel reaction A goes to B with rate constant k1 and A goes to C with r

Question

For a parallel reaction A goes to B with rate constant k1 and A goes to C with rate constant k2, you determine that the activation energies are 69.4 kJ/mol for k1 and 133.2 kJ/mol for k2. If the rate constants are equal at a temperature of 320 K, at what temperature (in K) will k1/k2 = 2? For a parallel reaction A goes to B with rate constant k1 and A goes to C with rate constant k2, you determine that the activation energies are 69.4 kJ/mol for k1 and 133.2 kJ/mol for k2. If the rate constants are equal at a temperature of 320 K, at what temperature (in K) will k1/k2 = 2? For a parallel reaction A goes to B with rate constant k1 and A goes to C with rate constant k2, you determine that the activation energies are 69.4 kJ/mol for k1 and 133.2 kJ/mol for k2. If the rate constants are equal at a temperature of 320 K, at what temperature (in K) will k1/k2 = 2?

Explanation / Answer

Ans: lnK=ln 0.5-(69.4-133.2/ RT)

ln(K1/K2)=ln 0.5-(69.4-133.2/ RT)

ln2=ln0.5-(-63.8/8.314*T)

0.301=-.301-(-63.8/8.314*T)

T=12.75+273=285.75 (Ans.)

285.753

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