I need help proposing the correct compound. From the mass spectrometry, I recogn

Question

I need help proposing the correct compound. From the mass spectrometry, I recognize that there must be 2 Cl atoms based upon the 100:66:11 ratio. From that, I got the molecular formula: C4H8Cl2 which has a DOU of 0 so no rings or pi bonds are present. The hydrogen NMR shows 8 hydrogens which confirms my molecular formula. There are two signals so I know there are only two H types. From that I identified that there are 2 different CH2s (4 CH2s total). The C NMR has two peaks so I thought the compound had to be symmetrical. What I got was Cl-CH2-CH2-CH2-CH2-Cl but what's causing me trouble is the fact that it says both H types are multiplets. Is my compound incorrect? How does the multiplet part make sense?

Unknown 553 Chemistry 2540 Spectroscopy Unknown -25 points Callam/Paul Information: Each spectra below was obtained from a pure compound. Mass Spectrum parent peaks (M) are listed for a examples. IR peaks listed are strong (s) unless otherwise indicated for signals above 1500 cm H NMR Spectra, the integral is given in number of hydrogens (HH) or as a relative ratio. Important coupling constants values are listed next to the peaks for some examples. For some spectra, a inset (grey box) is also given showing a "zoom n' on an important part of the spectrum Mass Spectrometry (not shown [M] 126 (100%), [M+2] 128 (66%), [M+4] 130 (11%) nfrared Spectroscopy (not shown): 2961, 2922 cm H Nuclear Magnetic Resonance 4H PPM 4H C Nuclear Magnetic Resonance 30 20 10 PPM

Explanation / Answer

The compound is showing two triplets and therefore the compound is correct. The compound is 1,4-dichloro butane.

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