Choose the balanced equation that depicts the formation of 1 mol of BaO(s) from

Question

Choose the balanced equation that depicts the formation of 1 mol of BaO(s) from its elements. 2Ba(s) + O_2(g) rightarrow BaO(s) Ba(s) + 1/2O_2(g) rightarrow BaO(s) 1/2Ba(s) + 1/2O_2(g) rightarrow BaO(s) Ba(s) + O_2(g) rightarrow BaO(s) What is the standard free energy of formation of 1.00 mol of BaO(s)? (This problem requires values in your textbook's specific appendices, which you can access through the OWLv2 MindTap Reader. You should the OWLv2 References' Tables this as the values will not match.) The standard free energy of formation of BaO(s) is -520.38 kJ/mol. What is the value of delta G degree when 454 g (1 lb) of BaO(s) is formed from the elements?

Explanation / Answer

Ans. Number of moles of BaO in 454.0 g sample = Mass/ Molar mass

                                                = 454 g/ (153.3264 g/mol)

                                                = 2.9610 mol

Give, dfG0 = - 520.38 kJ/ mol. That is, the formation of 1 mol (= 153.3264 g) BaO(s) is accompanies with the free energy change of -520.38 kJ/ mol.

Now,

Total dG0 for 454.0 g BaO = dfG0 x Moles of BaO(s)

                                    = (- 520.38 kJ/ mol) x 2.9610 mol

                                    = - 1540.85 kJ

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