A second enzyme, happyase, catalyzes the reaction of sad to happy. However, an i

Question

A second enzyme, happyase, catalyzes the reaction of sad to happy. However, an inhibitor, anger, has been found that slows the rate of the reaction. Use the data below to answer the questions regarding this enzyme. a. Make a Lineweaver-Burk plot for this data. Make sure that there are trendlines, labels with units, legend and appropriate scale on the graph. Please remove the guidelines. Make sure the graph is large enough to read. b. What type of enzymatic catalysis is taking place (based on your graph)? c. Determine the value for K_M and V_max.

Explanation / Answer

Lineweaver- burk plot can be represented as

1/V= (KM/Vmax)*1/S + 1/Vmax

So the plot of 1/V vs 1/S gives straight line with slope being KM/Vmax and intercept is 1/Vmax

the data points along with the plots are shown below

when there is no Anger, 1/Vmax ( intercept)= 0.041, Vmax= 1/0.041= 24.4uM/min

KM/Vmax( slope) = 0.072, KM= 24.4*0.072= 2mM

for the case of 5mM anger Vmax= 1/0.047= 21.27 uM/min, KM= 21.27*0.094 =2 mM

for the case of 10mM anger, Vmax= 1/0.059= 16.95 uM/min and KM=16.95*0.134= 2 mM

since KM remains same, the type of inhibition is non-competitive inhibition.

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