Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

30.0 mL of 0.10M HCI is mixed with 25ml, of 0.10M NaOH. What is the pH of the mi

ID: 509651 • Letter: 3

Question

30.0 mL of 0.10M HCI is mixed with 25ml, of 0.10M NaOH. What is the pH of the mixture? 12.0 2.0 2.3 11.7 13 A 0.20 M solution of a weak acid has a pH of 2. What is the % dissociation? 1% 2% 4% 5% 12.5% The K_a for hypochlorous acid (HClO) is 3.5 times 10^8. What is the pH of a 1.50M solution? 11.3 5.1 4.3 3.6 1.8 What is the concentration of the A^2 ion in the 0.20M solution? 4.0 times 10^9 3.7 times 10^4 8.0 times 10^9 7.4 times 10^4 1.9 times 10^2 A weak acid HA has a K_a value of 5.0 times 10^4. What is the K for the following reaction? A + H_2 O OH + HA 2.0 times 10^4 5.0 times 10^11 5.0 times 10^12 2.0 times 10^11 1.0 times 10^14 Determine the K_sp of BaSO_4 if it has a solubility of 0.778mg/L. MM(BaSO_4) = 233.4g/mol 15 times 10^5 3.4 times 10^-7 1.1 times 10^11 4.0 times 10^11. 3.6 times 10^12 21 & 22: Use the following information for questions. A Weak acid (H_2A) has a K_a1 of 126x10^-6 and a K_a2 of 8.0x10^-9. What is the pH of a 0.20M solution? 4.13 4.13 4.5 5.6 2.1 3.3 Determine the solubility (in g/L) of AgBr in a 0.30M solution of NaBr. (K_sp(AgBr) = 5.0 times 10^-13 MM = 188g/mol) 12 times 10^-10 3.1 times 10^-10 13 times 10^-5 2.1 times 10^-5 3.3 times 10^-1 Mg(OH)_2 has a K_sp of 5.6 times 10^-12 What would be the pH of a saturated solution of this salt? 3.8 10.3 10.1 11.2 11.9

Explanation / Answer

Question 18.

First, balance the reaction

HCl + NaOH = H2O + NaCl

then

calculate moles of each species

mol of HCl = MV = 30*0.1 = 3 mmol of H+

mol of NaOH = MV = 25*0.10 = 2.5 mmol of OH-

so

mmol of H+ left = 3-2.5 = 0.5 mmol of H+

recalcualte H+

Vtotal = 30+25 = 55 mL

[H+] = 0.5 mmol / 55 mL = 0.00909090 M

pH = -log(0.00909090) = 2.04

best answer is 2.0

Choose B

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote