What would be the effect (too high, too low, no effect) on the experimental valu

Question

What would be the effect (too high, too low, no effect) on the experimental value of the gas constant in each of the following scenarios? Justify your answers. A small amount (say 0.05 g) of NaNO_2 was lost when you transferred it to the Erlenmeyer flask (Step 2 in the Procedure) A small amount (say 0.05 g) of sulfuric acid was lost when you transferred it to the evaporating dish. (Step S In the procedure) You forgot to reduce the pressure in the flask (Step 3 in the procedure) The pressure sensor was overestimating pressure readings by 5 Torr The temperature probe was overestimating temperature readings by 5 degrees.

Explanation / Answer

Recall that

PV = nRT

so

R = PV/(nT)

a)

some NaNO2 is lost

so total moles of sample are not accoutned, the volume will be to low

so R will be to low (V is directly proportional to R)

b)

some acid is lost, so it will not react completely, the H2(g) or CO2(g) will not be formed completely, so

V is smaller, meaning that R is smaller as well

c)

If we do not reduce the pressure in flask, the P is acocaunted higher than it actually is, so P high, will make a lower R constant

d)

If P is higher than normal, the vlaue of R will be lower

e)

IF T is higher, then the R value will be lower as well, since they are inverselly proportional

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.