The dissolving of NaNO_3 (s) in pure water is represented by the equation above.

Question

The dissolving of NaNO_3 (s) in pure water is represented by the equation above.. What is the sign for Delta G for the dissolving of NaNO_3(s)? Justify your answer. What is the sign for Delta S for the dissolving of NaNO_3(s)? Justify your answer. The solubility of NaNO_3(s) increases with increasing temperature. What is the sign of Delta H for the dissolving process? Justify your answer. Is the answer you gave in part (a) consistent with your answers to parts are Explain. 2 N(g) rihgtarrow N_2 (g) Using the table of average bond energies below, determine the enthalpy change, reaction.

Explanation / Answer

(3)

(a) Since the dissolution reaction occurs spontaneously, the sign of deltaG is negative.

(b) As the solid NaNO3 spilts into ions and they freely move in the solution, so, the randomness or disorderness of the system increases. Hence entropy of this dissolution process increases.

(c) (i) Since with increase in temperature, dissolution of NaNO3 increases, indicating that the dissolution process is endothermic. Because raise in temperature favours endothermic reaction.

(c) (ii) Yes. As increase in temperature, increases the value of - TdeltaS term, which causes overall negative sign for deltaG.

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