If a peak in a^1 H NMR spectrum is split into a triplet, how many equivalent nei

Question

If a peak in a^1 H NMR spectrum is split into a triplet, how many equivalent neighboring protons does the proton have? Why would a carbon atom directly bonded to an oxygen atom have a greater chemical shift than a carbon atom two bonds away from an oxygen atom? If a^13 C NMR spectrum of an unknown shows 3 peaks, which molecules from the list above could be the unknown? For some of the^13 C NMR spectra, a peak was observed at ~77 ppm that was a triplet with a 1:1:1 intensity ratio. This peak is attributed to the carbon in the solvent (D-CCl_3, deuterated chloroform) being bonded to the deuterium isotope. Explain the splitting pattern of the peak. Why is it necessary to run more scans with^13 C NMR than^1 H NMR to get good signal-to-noise? The hydrogen atom bonded to oxygen in the alcohol group can be difficult to identify in^1 H NMR. Name at least two reasons for this difficulty.

Explanation / Answer

1) Peak in 1HNMR spectrum is split into triplet that is there is 3 number of peak for proton & 2 equivalent neighbouring proton.

that is

Triplet have 2 equivalent hydrogen neighbors=3 peaks

Singlet have equivalent hydrogen neighbors=1 peak

Doublet have 1 equivalent hydrogen neighbors=2 peaks

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