13 C NMR 1 H NMR Hi Our teacher assigned us to find the J-value of the given NMR

Question

13C NMR

1H NMR

Hi

Our teacher assigned us to find the J-value of the given NMR above. I don't need to find the compound. I just couldn't do the J-value (should be devided by 512 as the teacher told us).The following is an example of how your answer should be and how your answer should look like:

1H NMR (CDCl3) 7.25 (m, J=7Hz, 5H, benzene ring) 2.95 (t, J=7Hz, 2H, HB) 2.72 (t, J=7Hz, 2H, HA) 1.257 (s, 2H, amine) 13C NMR (CDCl3) 139.86 (CF) 128.872 (CE,G) 128.459 (CD,H) 126.148 (CC) 43.584 (CB) 40.160 (CA)

Thank you

Spin Works 4: Sample 1 13Cf1H No PPM 80 76 72 68 64 60 56 52 48 44 40 36 32 28 24 20 16 12 8 4 file: ma 3399 Desktop kine 13C120lfid expt: freq. of 0 ppm: 125.757789 MHz transmitter freq.: 125.774803 MHz processed size: 131072 complex points time domain size: 131072 points LB: 0.200 GF: 0.0000 width: 36496.35 Hz 290.1722 ppm 0.278445 Hz/pt Hz/cm: 421.367 ppm/cm: 3.35017 number of scans: 306

Explanation / Answer

Answer: HNMR (CDCl3) 4.2-4.1 (m, 1H)

1.8 (m, 3H), 1.69 (t, 3H J=3.8 Hz), 1.017 (t, 3H, J=5.8 Hz), 0.908 (t, 3H, J=5.8 Hz)

J Value calculate (0.923-0.894/500)x 106= 5.8 Hz

(1.031-1.002/500)x 106= 5.8 Hz

(1.696-1.677/500)x 106= 3.8 Hz

13 C NMR: 62.2,51.5, 43.2, 31.7, 26.4,20.9, 13.6, 12.0

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