Lab Report A. Determining AHon for an acid-base neutralization reaction Report a

Question

Lab Report A. Determining AHon for an acid-base neutralization reaction Report and an your data HCI data. mass coffee cup mass cup HCl solution S.25 mass HCl solution initial temperature of HCI volume of HCI Molarity of HCl moles HCl added NaOH data mass coffee cup mass cup NaOH solution S6.586 mass NaOH solution sa initial tempera of NaoH as volume of NaOH Molarity of NaOH moles NaOH added Reaction data total mass of mixed solutions initial temperature of solution (If HCl and NaOH differ by more than 0.1 o, a1. show the weighted average calculation) final temperature of solution 33. AT of solution. for actual amount of NaOH and HCI added) 162

Explanation / Answer

Hi

HCl Data:

mass of HCl solution= 72.164

volume of HCl= 71.9 ml= 0.0719 L

Molar mass of HCl= 36.5 g/gmole

moles of HCl added= 72.164/36.5 = 1.98 gmoles

Molarity of HCl= 1.98/0.0719 M= 27.50 M

NaOH Data:

mass of NaOH= 52.772 g

Volume of NaOH = 50 ml= 0.05 L

Molar mass of NaOH= 40 g/gmole

moles of NaOH= 52.772/40 moles= 1.32 gmoles

Molarity of NaOH= 1.32/0.05 M= 26.4 M

total mass of mixed solution= 124.936 g

Delta T= 33.9-21.75 = 12.15

Reaction between HCl and NaOH:

HCl + NaOH ----> NaCl + H2O

limiting reagent = NaOH

moles of HCl reacted = 1.32 gmoles

moles of NaOH reacted= 1.32 moles

Thank you

Related Questions

Navigate

• Browse (All)
• Browse L
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.