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ID: 510813 • Letter: R

Question

ry Bookmarks People Window Help Wo x M- North Carolina State Universi x "n Health Care Crisis Discussion x (3 celsius to kelvin Google Sea x g.com/biscmsmod da322 9102 Jump to... University. CH111-Spring17-McCARTY I Activities and Due Dates I Hw9 (CH 11) 0418 2017 1155 PM Gradebook Print Calculator Periodic Table Question 15 Sapung Learning Map A A7.35 u container holds a mixture of two gases at 17 C The temperature, are 0.168 atm 0.630 atm 0.170 mol of a what will the total pressure become? Previous Give up s view sek son Answer Next

Explanation / Answer

total pressure initially = sum of partial pressure of A and B = 0.630 atm + 0.168 atm = 0.798 atm

Now determne the initial moles of gas in the system from the total pressure

PV = nRT

P = 0.798 atm
V = 7.35 L
n = ? mol
R = gas constant = 0.082057 Latmmol^-1K^-1
T = temp in Kelvin = 290 K

n = PV / RT
= 0.798 atm x 7.35 L / (00.082057 x 290 K)
= 0.245 mol
= moles of gas initially in system

new moles = 0.245 mol + 0.170 mol
= 0.415 mol


Now work out what the new pressure will be

P = ? atm
V = 7.35 L
n = 0.415 mol
R = 0.082057 Latmmol^-1K^-1
T = 290 K

P = nRT / V
= 0.415 mol x 0.082057 x 290 / 7.35 L
= 1.34 atm