Calculate following solutions. 1.How many grams of solute are in each of the fol

Question

Calculate following solutions.

1.How many grams of solute are in each of the following solutions?

2.24.5 mL of a 6.00 M H3PO4 solution

3.What is the final volume V2 in milliliters when 0.871 L of a 45.1 % (m/v) solution is diluted to 23.9 % (m/v)?

4.A 740 mL NaCl solution is diluted to a volume of 1.39 L and a concentration of 7.00 M . What was the initial concentration C1?

Part A 0.550 mole glucose in 0.100 L of a glucose solution Express your answer with the appropriate units. Molarity =

Part B 71.5 g of HCl in 1.00 L of a HCl solution Express your answer with the appropriate units. Molarity =

Part C 37.0 g of NaOH in 350. mL of a NaOH solution Express your answer with the appropriate units.

Calculate the volume, in liters, of each of the following solutions that provides the given amount of solute:

Part D

7.80 mol of NaOH from a 11.8 M NaOH solution.

Express your answer with the appropriate units.

Part E

23.8 g of Na2SO4 from a 5.00 M Na2SO4 solution.

Express your answer with the appropriate units.

Part F

29.0 g of NaHCO3 from a 5.00 M NaHCO3 solution.

Calculate the volume, in liters, of each of the following solutions that provides the given amount of solute:

Part D

7.80 mol of NaOH from a 11.8 M NaOH solution.

Express your answer with the appropriate units.

Part E

23.8 g of Na2SO4 from a 5.00 M Na2SO4 solution.

Express your answer with the appropriate units.

Part F

29.0 g of NaHCO3 from a 5.00 M NaHCO3 solution.

Explanation / Answer

[2]. Molarity= no. Of moles of solute/V(L)

6. = n/24.5/1000

n. = 6×24.5/1000 = 0.147 moles

Mass of H3PO4=0.147×98= 14.406g

[3]. C1 x V1 = C2 x V2
where C1 and V1 is the concentration and volume of liquid 1 and C2, V2 is concentration and volume of liquid 2.
0.871L = 871mL
C1V1 = C2V2
45.1x 871 = 23.9 x V2
V2 = 1643.6mL

[4].
C1V1 =C2V2
C1 x 740 = 1390x 7
C1 = 13.14M

Part[A] : Molarity = no.of moles of solute/ V(L)

= 0.550/0.1=0.055M

Part[B] : Molarity = 71.5/35.5×1=2.01M

Part [C] : Molarity= 37×1000/40×350 =2.64M

Part[D] : Volume= no. Of moles/Molarity

= 7.8/11.8 =0.661L

Part [E] : Volume= 23.8/142×5 =0.033L

Part[F] : Volume=29/84×5 = 0.069L

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