1. If an aqueous solution has a glucose composition of 3.0% mass to volume, then

Question

1. If an aqueous solution has a glucose composition of 3.0% mass to volume, then how many grams of glucose will be in 1.00 x 102 milliliters of this solution?

a. 1.0 g b. 1.5g c. 2.0g d. 2.5g e. 3.0g

2. If a particular brand of beer has a grain alcohol composition of 3.2%, then how many milliliters of grain alcohol are in 1.00 x 102 millitiers of this brand of beer?

a. 1.1 ml b. 2.0ml c. 3.2ml d. 4.0ml e. 5.3 ml

3. how many milliters of a 12.0 Molar hydrochloric acid solution 12.0M HCL, are needed to prepare a 2.50 Liter solution of 0.120 M HCL?

a. 10.0 mL b.15.0mL c. 20.0mL d. 25.0mL e. 30.0mL

Explanation / Answer

1) Answer: (e)

Explanation:

Weight percentage = 3%

3 % means 3 g of the Glucose in 100 mL of the solution.

Here the question is how many grms in 1.00 x 102 mL

= 1 x 100

= 100 mL

Hence the weight of the glucose is 3 g.

2) Answer: (c)

Explanation:

3.2 % of the Alcohol means 3.2 mL of Alcohol in 100 mL of solvent

Here 1.00 x 102 mL given that means 100 mL

Hence the volume of Alcohol is 3.2 mL.

3) Preparation of 2.5 L, 0.12 M HCl:

wanted Molarity of HCl (M1) = 0.12

Wanted volume of HCl (V1 +V2)= 2.5 L

Concentration of HCl (M2)= 12 M

Volume of HCl (V2) = ?

M1V1=M2V2

0.12 x 2.5 = 12 x V2

V2 = (0.12 x 2.5) / 12

V2 = 0.3 / 12

V2 = 0.025 L

Hence the 12 M HCl volume is 0.025 L

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