Eile Edit View Hitory Bookmarks Ioels Help Master ngchemistry cha x https://sess

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Eile Edit View Hitory Bookmarks Ioels Help Master ngchemistry cha x https://session.masteringchemistry.com/myct/itemview?assignmentProble e q Search Introduction to Chemistry Chm101 Spring 2017 Exercise 8.18 Exercise 8.18 Part A For the reaction shown, calculate how many moles 53 mol of NH form when each amount of reactant Express your answer using two significant figures. completely reacts Submit My Answers GheUp Part B 2.25 mol NaH. Express your answer using three significant figures. O Submit My Answers Part C 6.3 x 10 2molNaH. Express your answer using two significant figures. Submit My Answers mol

Explanation / Answer

Part A

According to reaction 3 mole N2H4 produce 4 mole NH3 then 5.3 mole N2H4 produce =

5.3 X 4 / 3 = 7.067 mole of NH3

5.3 mole N2H4 produce 7.067 mole NH3

Part B

According to reaction 3 mole N2H4 produce 4 mole NH3 then 2.25 mole N2H4 produce =

2.25 X 4 / 3 = 3 mole of NH3

2.25 mole N2H4 produce 3 mole NH3

Part C

According to reaction 3 mole N2H4 produce 4 mole NH3 then 6.3 X 10-2 mole N2H4 produce =

6.3 X 10-2 X 4 / 3 = 0.084 mole of NH3

6.3 X 10-2 mole N2H4 produce 0.084 mole NH3

Part D

According to reaction 3 mole N2H4 produce 4 mole NH3 then 9.47 X 107 mole N2H4 produce =

9.47 X 107 X 4 / 3 = 1.2627 X 108 mole of NH3

9.47 X 107 mole N2H4 produce 1.2627 X 108 mole NH3

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