how many moles of each product will be formed when 35.0g of Fe2O3 react with 35.

Question

how many moles of each product will be formed when 35.0g of Fe2O3 react with 35.0g HCL? acual yield 100 yield 2.51. H 6 6 in 100 a salt and water: aqueous solution metal oxides can react with acids to form Fe2O3 (s) 6 HCl(aq) 2 FeCl3 (aq) 3 H20 ball unceo (a) How many moles of each product will be formed when 35.0 g of Fezo, react with 35.0 g ofHcl? (b) From part (a), how many grams of the excess reactant remain? (c) If the percent yield of FeCl3 is 92.5%, what is the actual yield in grams? th mules qrams Imole l Mo fez 03 35.00 mUICIr mCISS 0.219 mu

Explanation / Answer

Fe2O3(s) + 6 HCl(aq) -----------------> 2FeCl3(aq) + 3H2O(l)

according to balanced reaction

159.69 g Fe2O3 reacts with 6 x 36.5 g HCl

35 g Fe2O3 reacts with 35 x 6 x 36.5 / 159.69 = 48 g

but we have only 35 g HCl

so HCl is limiting reagent.

now

6 x 36.5 g HCl forms 2 moles FeCl3

35 g HCl forms 35 x 2 / 6x36.5 = 70 / 219 = 0.32

moles of FeCl3 formed = 0.32

6 x 36.5 g HCl forms 3 mole H2O

35 g HCl forms 35 x 3 / 6 x 36.5 = 105 / 219 = 0.48

moles of H2O formed = 0.48

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