An electrochemical cell is constructed for the purpose of determining the K_sp o

Question

An electrochemical cell is constructed for the purpose of determining the K_sp of copper (I) chloride, CuCl, at 25 degree C. One half-cell consists of a copper electrode in a 1.00 M solution of copper(I) nitrate. The other half-cell consists of a copper electrode in a saturated solution of copper (I) chloride. The measured cell potential is 0.175 V. Determine the concentration of copper (I) ion in the saturated copper(I) chloride solution and the value of K_sp for CuCl. Enter your answer in scientific notation. [Cu^+] = x times M Enter your answer in scientific notation. K_sp = times 10

Explanation / Answer

For concentration cell:

E = - 2.303*R*T/n*F * log ([Canode] /[Ccathode])

At 25 oC or 298 K, 2.303*R*T/F = 0.0592

E = - 0.0592/n * log ([Canode] /[Ccathode])

for E to be positive, the one with the higher concentration will be the anode since saturated solution will have [Cu+] < 1 M

so, saturated solution should be cathode

E = - 0.0592/n * log ([Canode] /[Ccathode])

0.175 = -0.0592/2 * log ( [Cu+] / 1)

log ( [Cu+] ) = -5.912

[Cu+] = 1.224*10^-6 M

Answer: [Cu+] = 1.224*10^-6 M

CuCl (s)       <—> Cu+(aq)   +   Cl- (aq)

                   s               s

Ksp = [Cu+] [Cl-]

Ksp = s*s

= (1.224*10^-6 )*(1.224*10^-6 )

= 1.498*10^-12

Answer: 1.498*10^-12

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