Calculate Delta S degree for the following reactions: a. CH_4 (g) + H_2O (l) rig

Question

Calculate Delta S degree for the following reactions: a. CH_4 (g) + H_2O (l) rightarrow CH_3OH (l) + H_2 (g) b. Fe_2O_3 (s) + 2 Al (s) rightarrow Al_2O_3 (s) + 2 Fe (s) c. C_2H_5OH (g) + 3 O_2 (g) rightarrow 2 CO_2 (g) + 3 H_2O (g) Calculate Delta G degree for the following reactions. Also indicate whether you reaction to occur spontaneously? a. CO (g) + 2 H_2 (g) rightarrow CH_4 (g) + H_2O (g) b. 2 H_2S (g) + 3 O_2 (g) rightarrow 2 H_2O(g) + 2 SO_2 (g) c. 2 CH_3OH (l) rightarrow 2 H_2O (l) + C_2H_4 (g)

Explanation / Answer

2)

a)

From data table:

Sof(CH4(g)) = 186.264 J/mol.K

Sof(H2O(l)) = 69.91 J/mol.K

Sof(CH3OH(l)) = 126.8 J/mol.K

Sof(H2(g)) = 130.684 J/mol.K

Balanced chemical equation is:

1CH4(g) + 1H2O(l) ---> 1CH3OH(l) + 1H2(g)

delta So rxn = 1*Sof(CH3OH(l)) + 1*Sof(H2(g)) - 1*Sof( CH4(g)) - 1*Sof(H2O(l))

delta So rxn = 1*126.8 + 1*130.684 - 1*186.264 - 1*69.91

delta So rxn = 1.31 J/mol.K

b)

From data table:

Sof(Fe2O3(s,hematite)) = 87.4 J/mol.K

Sof(Al(s)) = 28.3 J/mol.K

Sof(Al2O3(s)) = 50.92 J/mol.K

Sof(Fe(s)) = 27.78 J/mol.K

Balanced chemical equation is:

1Fe2O3(s) + 2Al(s) ---> 1Al2O3(s) + 2Fe(s)

delta So rxn = 1*Sof(Al2O3(s)) + 2*Sof(Fe(s)) - 1*Sof( Fe2O3(s)) - 2*Sof(Al(s))

delta So rxn = 1*50.92 + 2*27.78 - 1*87.4 - 2*28.3

delta So rxn = -37.52 J/mol.K

C)

From data table:

Sof(C2H5OH(g)) = 282.7 J/mol.K

Sof(O2(g)) = 205.138 J/mol.K

Sof(CO2(g)) = 213.74 J/mol.K

Sof(H2O(g)) = 188.825 J/mol.K

Balanced chemical equation is:

1C2H5OH(g) + 3O2(g) ---> 2CO2(g) + 3H2O(g)

delta So rxn = 2*Sof(CO2(g)) + 3*Sof(H2O(g)) - 1*Sof( C2H5OH(g)) - 3*Sof(O2(g))

delta So rxn = 2*213.74 + 3*188.825 - 1*282.7 - 3*205.138

delta So rxn = 95.84 J/mol.K

I am allowed to answer only 1 question at a time

Related Questions

Navigate

• Browse (All)
• Browse C
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.