Co(II) was used as an internal standard to analyze a sample of Ti(IV) with atomi
ID: 514562 • Letter: C
Question
Co(II) was used as an internal standard to analyze a sample of Ti(IV) with atomic absorption spectroscopy (AAS). A standard mixture containing 1.94 g Co/mL and 1.99 g Ti/mL measured by AAS produced a signal-to-signal ratio of 2.44 Ti: 1.00 Co.
A mixture was prepared by combining 4.50 mL of a Ti(IV) solution of unknown concentration with 3.00 mL of a 14.1 g/mL solution of Co(II). The absorbance of the mixture at the Ti(IV) wavelength was 0.162 and the absorbance at the Co(II) wavelength was 0.210.
Determine the concentration, in moles per liter, of Ti(IV) in the original unknown solution.
Explanation / Answer
Atomic Absorption Spectroscopy is an instrumental analysis technique for rapid trace metal analysis.It is based on element specific wavelength light absorption by ground state atoms in the flame or electrothermal graphite furnace. It finds immense applications in the analysis for trace metals in soils, lakes, rivers, oceans, and drinking water, pharmaceuticals, foods and beverages, geological and mineralogical samples, petroleum products, biological fluids and specimens and forensic analysis.
Atomic absorption spectroscopy (AAS) is a spectroanalytical procedure for the quantitative determination of chemical elements using the absorption of optical radiation (light) by free atoms in the gaseous state.
The relationship between the amount of light absorbed and the concentration of the analyte present in known standards can be used to determine unknown concentrations by measuring the amount of light they absorb. An atomic absorption spectrometer is simply an instrument in which these basic principles are applied to practical quantitative analysis.
A mixture was prepared by combining 4.50 mL of a Ti(IV) solution of (x) concentration with 3.00 mL of a 14.1 g/mL solution of Co(II)
The absorbance of the mixture at the Ti(IV) wavelength was 0.162 and the absorbance at the Co(II) wavelength was 0.210.
Ti(IV) / Co(II) = 3.0 * 14.1 / 4.5 * x = 0.21 / 0.162
hence, x = 12.1 g/mL
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.