R = 0.08206 (L middot atm/mol middot K) = 8.3145 (kg middot m^2/s^2 middot K mid
ID: 514926 • Letter: R
Question
R = 0.08206 (L middot atm/mol middot K) = 8.3145 (kg middot m^2/s^2 middot K middot mol) = 8.3145 (J/K middot mol); P = [nRT/(V-nb)] - n^2a/V^2; PV = constant (const. n, T); mu = (3RT/M_m)^-1/2; P_1V_1(T_1 = P_2V_2/T_2; P_r = sigma P_1 + P_2 + P_3 + ...; 1 mole = 6.02214129 times 10^23; t mol(gas) = 22.40 L; rho (density) = M_m/V; E-hv, v c/lambda, Delta E = -2.180 times 10^23 J/atom(1/hr^2 - 1/nr^2), h = 6.6260957 times 10^-34 J.s, c = 2.99792458 times 10^8 m/s. Which radiation has the lowest energy? a) gamma rays b) UV c) blue light d) red light c) radio waves Which compound contains both ionic and covalent bonds? a) KOCI b) H_2O c)CH_2Cl_2 d) MgCl_2 e) CH_4 What is the valence-shell electron configuration for the fourth-period element in Group VA? a) 5s^2 5p^2 b) 4s^2 5p^3 c) 4s^2 4p^3 d) 5s^2 4p^3 e) 4s^2 3d^3 Which of the following atoms has the SMALLEST atomic radius? a) Na b) B c) O d) P c) Cl a) What is Hund's Rule and b) how would you apply it to B, C, and N?Explanation / Answer
1.
Those who are having low frequency or higher wavelength have lowest energy according to the equation
E=hv
so radiowaves are having high wavelength or low frequency. So these are having low energy.
2.
KOCl has both ionic and covelant bond
3.
The electronic configuration is 4s24p3. because period number indicates principle quantum number
4.
Oxygen is having smallest atomic radius
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