1,1,1,2-Tetrafluoroethane has a molar mass of 102 g/mol. The percent composition
ID: 515258 • Letter: 1
Question
1,1,1,2-Tetrafluoroethane has a molar mass of 102 g/mol. The percent composition is 23.5% C, 1.96% H, and 74.5% F.What is the empirical formula of 1,1,1,2-tetrafluoroethane? Express your answer as a chemical formula. 1,1,1,2-Tetrafluoroethane has a molar mass of 102 g/mol. The percent composition is 23.5% C, 1.96% H, and 74.5% F.
What is the empirical formula of 1,1,1,2-tetrafluoroethane? Express your answer as a chemical formula. 1,1,1,2-Tetrafluoroethane has a molar mass of 102 g/mol. The percent composition is 23.5% C, 1.96% H, and 74.5% F.
What is the empirical formula of 1,1,1,2-tetrafluoroethane? Express your answer as a chemical formula.
Explanation / Answer
% C = 23.5, % H =1.96, % F = 74.5,
STEP 1
Convert the given % to grams assuming 100g sample is presene
C = 23.5 g , H = 1.96 g , F = 74.5 g
STEP 2
CONVERT THE MASS TO MOLES BY DIVIDING WITH MOLAR MASS
C = 23.5/12.01
= 1.96
H = 1.96/1.008
= 1.94
F = 74.5/19
= 3.92
STEP 3
DIVIDE THE OBTAINED MOLES WITH THE SMALLEST NUMBER OBTAINED TO GET RATIO OF ELEMENTS
C = 1.96/1.94
= 1(approx)
H = 1.94/1.94
=1
F = 3.92/1.94
2
SO THE RATIO OF ELEMENTS IS CHF2 = EMPERICAL FORMULA, MOLECULAR FORMULA = C2H2F4 OBTAINED BY DIVINDING MOLAR MASS WITH EMPERICAL FORMULA MASS AND MULTIPLYING THE OBTAINED NUMBER WITH EMPERICAL FORMULA
102/49 = 2 = (CHF2) X 2 = C2H2F4
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