If 0.450 moles of NaCl are dissolved in 95.0 mL of water. Which one is the molar

Question

If 0.450 moles of NaCl are dissolved in 95.0 mL of water. Which one is the molarity of the NaCl solution? a. 0.0047 M. b 0.21 M c. 2.1 M d. 4.7 M e. None of these are correct. Calcium hydroxide, Ca(OH)_2, is only slightly soluble in water. The K_sp expression for Ca(OH)_2 is: K_sp = [Ca][OH]^2 K_sp = [Ca][2 times OH] K_sp = [Ca^2+][2 times OH^-] K_sp = [Ca^2+][OH^-] K_sp = [Ca^2+][OH^-]^2 In the experiment of titration part II (please refer to your notes), the weight of your acid = 0.28 and Molarity of NaOH = 0.1 M (titrant). Based on the data that you collected during your experiment: V_1 (Trial 1) = 37.3 ml V_2 (Trial 2) = 36.1 ml V_3 (Trial 3) = 36.4 ml Calculate the molecular weight of the unknown acid. A student extracted caffeine from Pepsi cola; his favorite soda. Based on his lab experiment, the weight of caffeine residue was 0.23 mg in 70 ml of sample. How many mg of caffeine would he expect to find in a can of Pepsi cola if the levels of caffeine in per fl. oz can (355 ml) are 38mg? Please place the solubility product constants of the following compounds from the lowest to the greatest solubility.

Explanation / Answer

ans 1. d . 4.7 M

Molarity = no. of moles / volume of solution in litre

no of moles of NaCl = 0.450

volume = 95 ml = 0.095 litre

molarity = 0.450 / 0.095

= 4.73 M

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