Question 1 Use this information to answer the next five questions. In mice, the

Question

Question 1 Use this information to answer the next five questions. In mice, the allele for black coat color (B) is dominant over the brown allele (b). Two heterozygous mice are mated, and produce the following offspring: 20 black 4 brown What is the EXPECTED FREQUENCY of black and brown mice in the offspring from this cross? O a. 5 black: 1 brown O b. 3 black 1 brown O c 2 black 1 brown O d. 1 black 3 brown Question What is the EXPECTED NUMBER of offspring from this cross? a 20 black: 4 brown O b. 18 black: 6 brown O c 8 black 8 brown O d. 4 black: 20 brown Question 3 Using the chi-square formula (p. 65 in Pierce), what is the value of chi-sugare? O a. .21 b. .35 Question 4 O c .56 For this calculation, how many degrees of freedom are there? O d. .89 O d. 4 1 point save Question 5 Use your answers from questions 3 and 4 for Table 3.7 in your text (p. 650, to identify the corresponding value of p. Is the p-value that you get greater or less than 0.05? And does this mean there is a significant difference between the and expected numbers offspring? O a. p is greater than 0.05, so there is a significant difference C b. p is less than 0.05, so there is a significant difference O c p is greater than 0.05, so there is NOT a significant difference O d. p is less than 0.05, so there is NOT a significant difference

Explanation / Answer

Ans. a

here given AA(black) = 20 offsprings

aa (brown)+ 4 offspring

according to hardy weinberg equation equation:

P2 + Q2+2PQ=1

P= frequency of dominant allel A and Q = frequency of recessive allele a.

therefore,

Q2= 24/6= 1/6= 0.166, hence Q=0.407

P+Q= 1

therefore,

P= 0.593

frequency of allele AA= =.5932=0.351

aa=0.165

Aa= 0.482

total offspring will be With allele AA= 24x0.351= 8.4=8

aa= 24x0.165= 3.96=4

Aa= 0.482x24= 11.568=12

all AA and Aa will be black= 20

aa or Brown = 4

therefore ratio will be 20:4= 5:1

there will be 5 Black and 1 brown offspring.

2. a

As explained above

there will be 20Black offspring and 4 brown offsprings.

3. c

Chi square formula

X2=sum(Observed value - Expected value)2/Expected value

= {20-(11.586+8.4)}2/11.586+8.4=0.0007+4-3.96/3.96= 0.0007+0.0100= 0.0107

Expected ratio of such crossesa= 3:1

therefore expected black offspring= 3/4X20= 15

1/4X4=1

putting values in above chi square formula,

X2=(20-15)/15=1.66+(4-1)2/4=2.25=3.91

which is nearly equal to 3.5

4. degree of freedom in this question= 2-1=1

5. c

Using chi square table with respect to degree of freedom

Our degree of freedom is 1 and chi square value is 3.5

hence we get that we have P greater than 0.05

It showsthat there is not signifiacant difference.

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