The true value of Ksp for Ca(OH)2 is 5.5 times 10^-6. Use this value to calculat
ID: 516131 • Letter: T
Question
The true value of Ksp for Ca(OH)2 is 5.5 times 10^-6. Use this value to calculate the % error between the experiment and true Ksp according to the equation: %error= Ksp(experimental) - Ksp(true)/Ksp(true) times 100 The following below is the data received from the experiment Trial 1 Experimental Ksp: 1.67 times 10^-5 Trial 2 Experimental Ksp: 2.00 times 10^-5 Trial 3 Experimental Ksp: 2.00 times 10^-5 Average Experimental Ksp: 1.89 times 10^-5 I was wondering which experimental Ksp trial would I have to use in order to solve this problem, can I just pick one or would I have to use the average experimental Ksp in order to solve it.Explanation / Answer
True Ksp value of Ca(OH)2 = 5.5 * 10^-6
Trail1 Ksp1 = 1.67 * 10^-5
Trail2 Ksp2 = 2 * 10^-5
Trail3 Ksp3 = 2 * 10^-5
Average Ksp = 1.89 * 10^-5
% error = (Ksp (experrimental) - Ksp(true))/Ksp(true) * 100
for trail1
% error = ((1.67*10^-5) - (5.5*10^-6))/(5.5*10^-6) * 100
% error = 203.64%
for trail2
% error = ((2*10^-5) - (5.5*10^-6))/(5.5*10^-6) * 100
% error = 263.64%
for trail3
% error = ((2*10^-5) - (5.5*10^-6))/(5.5*10^-6) * 100
% error = 263.64%
for average value
% error = ((1.89*10^-5) - (5.5*10^-6))/(5.5*10^-6) * 100
% error = 243.64%
In all the given values % error is less in trail1 so we have to consider that value in case of accuracy and we have to take trail2 or trail3 value in case pricision eventhough the %error is more.
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