Given the following information: Rate = [Br^-][C][H^+]^2 i. Give the order for e

Question

Given the following information: Rate = [Br^-][C][H^+]^2 i. Give the order for each substance in the reaction. Give the overall order for the reaction. ii. By what factor does the rate change for each of the following: a) [Br^-] is tripled b) [C] is quadrupled c) [H^+] is halved (b) Give the units of the rate constant if a reaction has each of the following overall orders and the reaction is measured in hours. i. 3/2 ii. 4^th (c) Give the overall reaction order that corresponds to a rate constant with each of the following units. i. M^5/2min^-1 ii. sec^-1

Explanation / Answer

19)

a)

i)

overall order = 1 + 1 + 2 = 4

ii)a) since order of Br- is 1 , tripling [Br-] will triple the reaction rate of reaction

Answer: 3 times

ii)b) since order of C is 1 , quadrupling [C] will quadruple the reaction rate of reaction

Answer: 4 times

ii)c) since order of H+ is 2 , halfing [H+] will make the reaction rate as 1/4 times

Answer: 1/4 times

19)

b)

i) rate = k [A]^3/2

M/hr = k * M^3/2

k = M-1/2 . hr-1

Answer: M-1/2 . hr-1

ii) rate = k [A]^4

M/hr = k * M^4

k = M-3 . hr-1

Answer: M-3 . hr-1

19)

c)

i)

rate = k [A]

M/min = M^5/2 min-1 [A]

[A] = M^-3/2

order is -3/2

ii)

rate = k [A]

M/s-1 = s-1 [A]

[A] = M

order is 1

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