Consider the titration of HC_2 H_3 O_2 with NaOH. Let\'s say that you need to ad

Question

Consider the titration of HC_2 H_3 O_2 with NaOH. Let's say that you need to add 0.0221 moles of NaOH in order for the indicator dye to change color. How many moles of HC_2 H_3 O_2 must you have had to start? Consider the titration of HC_2 H_3 O_2 with NaOH. If it requires 0.00375 mol of NaOH to reach the endpoint, and if we had originally placed 15.23 mL of HC_2 H_3 O_2 in the Erienmeyer flask to be analyzed, what is the molarity of the original HC_2 H_3 O_2 solution? Consider the titration of H_3 C_6 H_5 O_7 with NaOH. Let's say that you need to add 0.0353 moles of NaOH in order for the indicator dye to change color. How many moles of H_3 C_6 H_5 O_7 must you have had to start? Report answer to the correct sig figs. Do not provide units.

Explanation / Answer

Answer :

8) HC2H3O2 i.e. Acetic acid is a monoprotic acid hence on titration against NaOH which is als mono acidic base will stoichiometrically require same # of moles for complete neutralization.The colour change of of solution due to indicator is because of presence of excess of base added after neutralization of acid.

So approximately,

# of moles of Acetic acid = # of moles of NaOH = 0.0221 moles.

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