I JUST NEED HELP WITH PART B Three gases (8.00 g of methane, CH4, 18.0 g of etha
ID: 516955 • Letter: I
Question
I JUST NEED HELP WITH PART B
Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0-L container. At 23.0 C, the total pressure in the container is 5.50 atm .
A) Calculate the partial pressure of each gas in the container. Express the pressure values numerically in atmospheres, separated by commas. Enter the partial pressure of methane first, then ethane, then propane.
Answerd: 1.21, 1.45, 2.84 atm
B) A gaseous mixture of O2 and N2 contains 34.8 % nitrogen by mass. What is the partial pressure of oxygen in the mixture if the total pressure is 465 mmHg ?
Explanation / Answer
B)
mass of N2 = 34.8 g
mass of O2 = 65.2 g
moles of N2 = 34.8 / 28 = 1.243
moles of O2 = 65.2 / 32 = 2.0375
total moles = 3.2805
mole fraction of N2 = 0.379
mole fraction of O2 = 0.621
total pressure = 465 mmHg
partial pressure of O2 = 0.621 x 465 = 288.8 mmHg
partial pressure of oxygen = 288.8 mmHg
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