A schematic of the cycle of copper reactions is shown below. (2) Cu(s) Cu(NO32 (
ID: 518074 • Letter: A
Question
A schematic of the cycle of copper reactions is shown below. (2) Cu(s) Cu(NO32 (aq) HNO3 Cu(OH)2(s) NaOH Zn(s) H2SO4 CuSO4 (aq) CuO(s) (4) Solid copper is initially dissolved in concentrated nitric acid (1), producing Cu(NO3) and gaseous NO2. To this solution, sodium hydroxide is added (2), resulting in the precipitation of Cu(oH)2. Upon heating (3), the Cu(oH)2 decomposes to cuo. sulfuric acid is added to the Cuo (40, producing Cuso,. Finally, solid zinc is added (5) and solid copper is regenerated. By massing the copper before and after this cycle of eactions, the percent recovery can be calculated. mass Cu (after) x 100 mass Cu (before) Percent Recovery TY PRECAUTIONS centrated (16 M) nitric acid is a potent oxidizing agent, which may produc skin discoloration, and lung irritation. As such, the nitric acid mu ain in the fume hood at all times. In addition, the dissolution of copper wire in th ic acid produces toxic NO2 gas; this reaction must also take place in the fume hoo lly, methanol is flammable and its vapors are toxic. Use it in the fume hood an it away from open flames.Explanation / Answer
The mass or copper before the reaction = 0.5674g
The mass of copper nitrate formed = 0.8024g
Molar mass of copper nitrate is = 63.5 + (2*28 +16*6) = 63.5 + 56 + 96 = 215.5 g
In 215.5 g copper nitrate = 63.5g copper is present
In 1g copper nitrate = 63.5/215.5g copper present
In 0.8024g copper nitrate = (63.5/215.5)*0.8024g copper present = 0.3672 g copper preswnt
It means the mass of copper after the reaction is = 0.3672g
hence percentage yeild of the reaction is = mass of copper after/mass of copper befor *100 = (0.3672/0.5674)*100 = 64.71% ans.
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