Calculate the standard entropy. Delta S degree _rxn of the following reaction at

Question

Calculate the standard entropy. Delta S degree _rxn of the following reaction at 25.0 degree C using the data in this table. The standard enthalpy of the reaction. Delta W degree _rxn is - 633.1 kJ middot mol^-1 3C_2H_2 (g) rightarrow C_6H_6(l) Delta S degree _rxn = J middot K^-1 mol^-1 Then, calculate the standard Gibbs free energy of the reaction, Delta G degree _rxn Delta G degree _rxn = kJ middot mol^-1 Finally, determine which direction the reaction is spontaneous as written at 25.0 degree C and standard pressure. forward reverse both neither

Explanation / Answer

DeltaS0rxn = deltaH0rxn / T

= - 633.1 / 298

= - 2.12 kJ/K.mol

= - 0.00212 J/K.mol

DeltaG0rxn = deltaH0rxn - TdeltaS0rxn

= - 633 - 298 ( - 0.00212)

= - 632.4 kJ/mol

Since deltaG0rxn is negative, The reaction is spontaneous in forward direction.

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