Circle the question that have been assigned. 1. Sodium metal is also readily oxi
ID: 519644 • Letter: C
Question
Circle the question that have been assigned. 1. Sodium metal is also readily oxidized by oxygen. If the product of the reaction were dissolved in water, what would be the color of the litmus for a litmus test? Explain. What is the product? 2. Oxygen gas has an oxidizing strength comparable to that of nitric acid. Patina is a green or greenish-blue coating that forms on copper metal in the environment. Account for its formation. 3. Test tube 7. Does the ferrous ion in the Fe (NH_4)_2 (SO_4)_2 solution function as an oxidizing agent or a reducing agent? Explain. 4. Test tube 8. a. What was the color change of the I^- in the reaction? b. Does the I^- solution function as an oxidizing agent or a reducing agent? Explain. 5. 1 Eliseo couldn't find the 6 M HCl and so used 6 M HNO_3 for testing the metals instead. His logic? Both are strong acids. Explain how the results of the experiment would have been different. 6. Single displacement, double displacement, and decomposition reactions may all be redox reactions. Identify the type of redox reactions in Part C. Explain. 7. a. On the basis of your intuitive understanding of the chemical properties of sodium and gold, where in your activity series would you place sodium and gold? b. Will hydrochloric acid react with gold metal to produce gold (III) ions and hydrogen gas? Explain.Explanation / Answer
2. Patina ia a coating of Copper salts like oxides, carbonates, sulfides, or sulfates formed on the surface during exposure to atmospheric oxygen. In this process Cu(0) is converted to Cu(II) like the reaction with Nitric Acid.
3. In Mohr Salt Ferrous ion behaves as a reducing agent as Fe2+ is oxidized to Fe3+ in the reactions.
7. a. Sodium being an alkali metal is much more reactive as compared to noble metal Gold. Therefore, Sodium is at a higher position as compared to Gold.
b. Gold being a noble metal is placed below Hydrogen in the activity series. Therefore Gold will not react with HCl to liberate hydrogen gas.
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