The process of dissolving sugar in water is endothermic but this is not true for
ID: 520302 • Letter: T
Question
The process of dissolving sugar in water is endothermic but this is not true for all compounds. Dissolving vinegar (acetic acid) in water, for example, is exothermic. Will increasing the temperature increase the solubility of vinegar in water? (No/Sometimes/Yes), because increasing the temperature (shifts the equilibrium towards the products/provides more heat for the reaction to overcome the activation energy/shifts the equilibrium towards the reactants/breaks the chemical bonds in vinegar/makes the molecules move faster) and (does not change, increases/decreases) the solubility of vinegar in water. The process of dissolving sugar in water is endothermic but this is not true for all compounds. Dissolving vinegar (acetic acid) in water, for example, is exothermic. Which side of the reaction will heat appear for the dissolution of vinegar into water? a. Heat does not appear in the reaction b. product side c. reactant side c. both sides For the rock candy to form, sugar needs to come out of solution slowly to allow crystal formation. Would adding more sugar after the heat is turned off be an effective way to create crystals? Adding more sugar will shift equilibrium toward (neither reactant or product/aqueous sugar/both reactant and product/solid sugar). This would (leave undissolved suager crystals/occur slowly/occur quickly/supersaturate the solution), so the rock candy (will/will not) crystalize well.Explanation / Answer
1) An exothermic reaction is one which releases heat to the surroundings. The surroundings are therefore, warmer after the reaction. An exothermic reaction is favored by low temperatures. High temperatures are not conducive for an exothermic reaction and the reaction proceeds in the direction where heat energy is absorbed. Therefore, the reverse reaction is favored.
Increasing the temperature will not increase the solubility of vinegar in water, because an increase in temperature shifts the equilibrium towards the reactants and decreases the solubility of vinegar in water.
2) Heat is released in the dissolution of vinegar in water. Therefore, heat is lost from the product side. Hence, heat must appear on the reactant side.
Ans: (C) Reactant side
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