1)What is the mass of recovered solids? 2) % yield (percentage of solids recover

Question

1)What is the mass of recovered solids? 2) % yield (percentage of solids recovered): 3) % error?
Name: Mass of filter paper: 2. Mass of the empty evaporating dish: B. Mass of the evaporating dish and mixture 4. Mass of the initial mixture: Part A. Separation of Iron 5. Mass of iron and the evaporating dish 6. Mass of iron collected: 7. Mass of remaining sample and Beaker 1) Part B. Separation of Naphthalene 8. Mass of sample and Beaker (1) after sublimation: 9. Mass of naphthalene (by subtraction): Part C. Separation of NaCl 10. Mass of Flask (2) and boiling stones: 11. Mass of Flask (2), stones, and dry NaCI: 12. Mass of NaCl: Part D. Mass of Sio2 13. Mass of SiO2 and filter paper 14. Mass of SiO2 Calculation: Show calculations for step 15-21: 15. Percentage of Iron: 0, 83x100 16. Percentage of Naphthalene: 17. Percentage of NaCl: Report Sheet Partner(s) Name: 546g 0.00 67s o So 28,3% 4% Experiment: Separation of Mixture

Explanation / Answer

From the above shown data,

Original mixture = 1.9932 g

mass of Fe = 0.283 g

mass% Fe = 0.283 x 100/1.9932 = 14.20%

mass of Naphthalene = 0.004 g

mass% Naphthalene = 0.004 x 100/1.0032 = 0.20%

mass of NaCl = 0.5767 g

mass% NaCl = 0.5767 x 100/1.9932 = 28.93%

mass of SiO2 = 1.0507 g

mass% SiO2 = 1.0507 x 100/1.9932 = 52.71%

1) Mass of recovered solids = Fe + Naphthalene + NaCl + SiO2 = 2.3707 g

3) %error = (2.3707 - 1.9932) x 100/1.9932 = 18.94%

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